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Prove f1cdmsn
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BTernaryTau committed Dec 5, 2024
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Expand Up @@ -68516,6 +68516,19 @@ more bytes (305 versus 282). (Contributed by AV, 3-Feb-2021.)
UOUPURWFVBCVIHZWHWFWIVBWFWIEBCULUMUNUOUQ $.
$}

${
$d A x y $. $d A y z $. $d B y z $. $d F y z $.
$( If a one-to-one function with a nonempty domain has a singleton as its
codomain, its domain must also be a singleton. (Contributed by
BTernaryTau, 1-Dec-2024.) $)
f1cdmsn $p |- ( ( F : A -1-1-> { B } /\ A =/= (/) ) -> E. x A = { x } ) $=
( vy vz csn wf1 c0 wne wa cv wceq wral wrex wex wcel w3a cfv fvconst issn
wf f1f 3adant3 3adant2 eqtr4d syl3an1 f1veqaeq 3impb mpd 3expia reximdva0
wi ralrimiv syl ) BCGZDHZBIJKELZFLZMZFBNZEBOBALGMAPUQVAEBUQURBQZKUTFBUQVB
USBQZUTUQVBVCRURDSZUSDSZMZUTUQBUPDUBZVBVCVFBUPDUCVGVBVCRVDCVEVGVBVDCMVCBC
URDTUDVGVCVECMVBBCUSDTUEUFUGUQVBVCVFUTUMBUPURUSDUHUIUJUKUNULEFABUAUO $.
$}

${
$d A f x $. $d D f x $. $d V f x $. $d f ps $. $d ph x $.
$( TODO: there must be a more elegant way to prove this theorem using
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