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use std::io::Read; | ||
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fn get_word() -> String { | ||
let stdin = std::io::stdin(); | ||
let mut stdin=stdin.lock(); | ||
let mut u8b: [u8; 1] = [0]; | ||
loop { | ||
let mut buf: Vec<u8> = Vec::with_capacity(16); | ||
loop { | ||
let res = stdin.read(&mut u8b); | ||
if res.unwrap_or(0) == 0 || u8b[0] <= b' ' { | ||
break; | ||
} else { | ||
buf.push(u8b[0]); | ||
} | ||
} | ||
if buf.len() >= 1 { | ||
let ret = String::from_utf8(buf).unwrap(); | ||
return ret; | ||
} | ||
} | ||
} | ||
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fn get<T: std::str::FromStr>() -> T { get_word().parse().ok().unwrap() } | ||
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// Segment Tree. This data structure is useful for fast folding on intervals of an array | ||
// whose elements are elements of monoid I. Note that constructing this tree requires the identity | ||
// element of I and the operation of I. | ||
// Verified by: yukicoder No. 2220 (https://yukicoder.me/submissions/841554) | ||
#[derive(Clone)] | ||
struct SegTree<I, BiOp> { | ||
n: usize, | ||
orign: usize, | ||
dat: Vec<I>, | ||
op: BiOp, | ||
e: I, | ||
} | ||
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impl<I, BiOp> SegTree<I, BiOp> | ||
where BiOp: Fn(I, I) -> I, | ||
I: Copy { | ||
pub fn new(n_: usize, op: BiOp, e: I) -> Self { | ||
let mut n = 1; | ||
while n < n_ { n *= 2; } // n is a power of 2 | ||
SegTree {n: n, orign: n_, dat: vec![e; 2 * n - 1], op: op, e: e} | ||
} | ||
// ary[k] <- v | ||
pub fn update(&mut self, idx: usize, v: I) { | ||
debug_assert!(idx < self.orign); | ||
let mut k = idx + self.n - 1; | ||
self.dat[k] = v; | ||
while k > 0 { | ||
k = (k - 1) / 2; | ||
self.dat[k] = (self.op)(self.dat[2 * k + 1], self.dat[2 * k + 2]); | ||
} | ||
} | ||
// [a, b) (half-inclusive) | ||
// http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ | ||
#[allow(unused)] | ||
pub fn query(&self, rng: std::ops::Range<usize>) -> I { | ||
let (mut a, mut b) = (rng.start, rng.end); | ||
debug_assert!(a <= b); | ||
debug_assert!(b <= self.orign); | ||
let mut left = self.e; | ||
let mut right = self.e; | ||
a += self.n - 1; | ||
b += self.n - 1; | ||
while a < b { | ||
if (a & 1) == 0 { | ||
left = (self.op)(left, self.dat[a]); | ||
} | ||
if (b & 1) == 0 { | ||
right = (self.op)(self.dat[b - 1], right); | ||
} | ||
a = a / 2; | ||
b = (b - 1) / 2; | ||
} | ||
(self.op)(left, right) | ||
} | ||
} | ||
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struct Rng { | ||
x: u64, | ||
} | ||
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impl Rng { | ||
fn new() -> Self { | ||
use std::hash::{Hasher, BuildHasher}; | ||
let hm = std::collections::HashMap::<i32, i32>::new(); | ||
let mut hash = hm.hasher().build_hasher(); | ||
hash.write_u32(8128); | ||
Rng { | ||
x: hash.finish(), | ||
} | ||
} | ||
fn next(&mut self) -> u32 { | ||
let a = 0xdead_c0de_0013_3331u64; | ||
let b = 2457; | ||
self.x = self.x.wrapping_mul(a).wrapping_add(b); | ||
let x = self.x; | ||
((x ^ x << 10) >> 32) as _ | ||
} | ||
} | ||
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// https://yukicoder.me/problems/no/2761 (3) | ||
// 文字列の位置が固定 (シフトしない) であるため、特にローリングハッシュである必要はなく、位置ごとに乱数を生成すれば良い。 | ||
// また ModInt である必要もないので xor で演算している (zobrist hash と同様)。これで解説より定数倍高速である。 | ||
fn main() { | ||
let mut rng = Rng::new(); | ||
let n: usize = get(); | ||
let l: usize = get(); | ||
let q: usize = get(); | ||
let mut s = vec![]; | ||
for _ in 0..n { | ||
s.push(get_word().bytes().collect::<Vec<_>>()); | ||
} | ||
let mut val = vec![[0u64; 26]; l]; | ||
for i in 0..l { | ||
for j in 0..26 { | ||
val[i][j] = rng.next() as u64; | ||
val[i][j] |= (rng.next() as u64) << 32; | ||
} | ||
} | ||
let mut st = vec![SegTree::new(l, |x, y| x ^ y, 0); n]; | ||
for i in 0..n { | ||
for j in 0..l { | ||
let idx = (s[i][j] - b'a') as usize; | ||
st[i].update(j, val[j][idx]); | ||
} | ||
} | ||
for _ in 0..q { | ||
let ty: i32 = get(); | ||
if ty == 1 { | ||
let k = get::<usize>() - 1; | ||
let c: char = get(); | ||
let d: char = get(); | ||
let v = val[k][(d as u8 - b'a') as usize]; | ||
for i in 0..n { | ||
if s[i][k] == c as u8 { | ||
s[i][k] = d as u8; | ||
st[i].update(k, v); | ||
} | ||
} | ||
} else { | ||
let mut sum = 0; | ||
let t = get_word().bytes().collect::<Vec<_>>(); | ||
for i in 0..t.len() { | ||
sum ^= val[i][(t[i] - b'a') as usize]; | ||
} | ||
let mut ans = 0; | ||
for i in 0..n { | ||
if st[i].query(0..t.len()) == sum { | ||
ans += 1; | ||
} | ||
} | ||
println!("{}", ans); | ||
} | ||
} | ||
} |
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