Json Plugin

This behavior is designed to CakePHP 2.0 and give a performed way to response JSON requests.

NOTE: The CakePHP 2.1 has support to Json View. So you DON'T need to use this plugin. You can check the CakePHP Documentation how to use.

Installation

• Clone from github: from your app directory, run git clone git://github.com/jrbasso/json_plugin.git Plugin/Json
• Add as a git submodule: from you app directory, run git submodule add git://github.com/jrbasso/json_plugin.git Plugin/Json
• Download an archive from github and extract it in app/Plugin/Json

If you are not using CakePlugin::loadAll(), add CakePlugin::load('Json'); in your bootstrap.

Usage

Directly from your Controller

<?php
App::uses('JsonResponse', 'Json.Network');
class UserController extends AppController {
	public function index() {
		$data = $this->User->find('all');
		return new JsonResponse($data);
	}
}
?>

This way is not compatible with MVC archicture, but is the most easy and fast way to response JSON requests.

Setting json variable in Controller

<?php
class UserController extends AppController {
	public $view = 'Json.Json';
	public function index() {
		$data = $this->User->find('all');
		$this->set('json', $data);
	}
}
?>

This is the fast way in MVC, but do not load helpers and view files. Just transform the $data in JSON.

Using view files (recommended)

Set the data in your controller:

<?php
class UserController extends AppController {
	public $view = 'Json.Json';
	public function index() {
		$users = $this->User->find('all');
		$this->set(compact('users'));
	}
}
?>

Format the json in your view file:

<?php
$json = array('users' => array());
foreach ($users as $user) {
	$json['users'][] = $user['User']['username'];
}
$this->set(compact('json'));
?>

License

MIT License (http://www.opensource.org/licenses/mit-license.php)