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Added binary to decimal, decimal to binary, hex to decimal and decima…
…l to hex implementations
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""" | ||
Author: OMKAR PATHAK | ||
Created On: 23 August 2017 | ||
""" | ||
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def decimal_to_binary(number): | ||
''' | ||
This function calculates the binary of the given decimal number | ||
:param number: decimal number in string or integer format | ||
:return : string of the equivalent binary number | ||
Algo: | ||
1. Divide the decimal number by 2. Treat the division as an integer division. | ||
2. Write down the remainder (in binary). | ||
3. Divide the result again by 2. Treat the division as an integer division. | ||
4. Repeat step 2 and 3 until result is 0. | ||
5. The binary value is the digit sequence of the remainders from the last to first. | ||
''' | ||
if isinstance(number, str): | ||
number = int(number) | ||
binary = [] | ||
while number >= 1: | ||
remainder = number % 2 | ||
binary.append(remainder) | ||
number = number // 2 | ||
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return ''.join(map(str, binary[::-1])) | ||
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def binary_to_decimal(number): | ||
''' | ||
This function calculates the decimal of the given binary number | ||
:param number: decimal number in string or integer format | ||
:return : integer of the equivalent decimal number | ||
Algo: | ||
1. Get the last digit of the binary number. | ||
2. Multiply the current digit with (2^power), store the result. | ||
3. Increment power by 1. | ||
4. Repeat from step 2 until all digits have been multiplied. | ||
5. Sum the result of step 2 to get the answer number. | ||
''' | ||
decimal = [] | ||
number = list(str(number)[::-1]) | ||
for i in range(len(number)): | ||
decimal.append(int(number[i]) * (2 ** i)) | ||
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return sum(decimal) | ||
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def decimal_to_hex(number): | ||
''' | ||
This function calculates the hex of the given decimal number | ||
:param number: decimal number in string or integer format | ||
:return : string of the equivalent hex number | ||
Algo: | ||
1. Divide the decimal number by 16. Treat the division as an integer division. | ||
2. Write down the remainder (in hexadecimal). | ||
3. Divide the result again by 16. Treat the division as an integer division. | ||
4. Repeat step 2 and 3 until result is 0. | ||
5. The hex value is the digit sequence of the remainders from the last to first. | ||
''' | ||
if isinstance(number, str): | ||
number = int(number) | ||
hexadec = [] | ||
hex_equivalents = {10:'A', 11:'B', 12:'C', 13:'D', 14:'E', 15:'F'} | ||
while number >= 1: | ||
remainder = number % 16 | ||
if remainder < 10: | ||
hexadec.append(remainder) | ||
elif remainder >= 10: | ||
hexadec.append(hex_equivalents[remainder]) | ||
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number = number // 16 | ||
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return ''.join(map(str, hexadec[::-1])) | ||
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def hex_to_decimal(number): | ||
''' | ||
This function calculates the decimal of the given hex number | ||
:param number: hex number in string or integer format | ||
:return : integer of the equivalent decimal number | ||
Algo: | ||
1. Get the last digit of the hex number. | ||
2. Multiply the current digit with (16^power), store the result. | ||
3. Increment power by 1. | ||
4. Repeat from step 2 until all digits have been multiplied. | ||
5. Sum the result of step 2 to get the answer number. | ||
''' | ||
decimal = [] | ||
decimal_equivalents = {'A':10, 'B':11, 'C':12, 'D':13, 'E':14, 'F':15} | ||
number = list(str(number)[::-1]) | ||
for i in range(len(number)): | ||
try: | ||
if int(number[i]) < 10: | ||
decimal.append(int(number[i]) * (16 ** i)) | ||
except ValueError: | ||
decimal.append(decimal_equivalents[number[i]] * (16 ** i)) | ||
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return sum(decimal) | ||
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print(hex_to_decimal('7DE')) |