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98_validate_binary_search_tree.py
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98_validate_binary_search_tree.py
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'''
98. Validate Binary Search Tree
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
Example 1:
2
/ \
1 3
Input: [2,1,3]
Output: true
Example 2:
5
/ \
1 4
/ \
3 6
Input: [5,1,4,null,null,3,6]
Output: false
Explanation: The root node's value is 5 but its right child's value is 4.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
def isValidBST(self, root: TreeNode) -> bool:
'''
class Solution(object):
def isValidBST(self, root):
# recursion
def helper(node, lower, upper):
if not node:
return True
val = node.val
if val <= lower or val >= upper:
return False
if not helper(node.right, val, upper):
return False
if not helper(node.left, lower, val):
return False
return True
return helper(root, float('-inf'), float('inf'))
# def isValidBST(self, root: TreeNode) -> bool:
# return self.helper(root, float('-inf'), float('inf'))
# def helper(self, node, lower, upper):
# if not node:
# return True
# val = node.val
# if val <= lower or val >= upper:
# return False
# if not self.helper(node.right, val, upper):
# return False
# if not self.helper(node.left, lower, val):
# return False
# return True
if __name__ == '__main__':
# begin
s = Solution()
print(s.isValidBST([5, 1, 4, null, null, 3, 6]))