about allowReconnection method, how to get a newer reconnectionToken

[VicentGogh2025]

this.allowReconnection(client, 6000).then((isReconnected) => {
          if (isReconnected) {
            console.log("success", client.sessionId);
            if (this.state.players.has(client.sessionId)) {
              let reconnP = this.state.players.get(client.sessionId);
                reconnP.isOnline = true;
                const reconnToken = this.getRealReconnToken(this.roomId,client._reconnectionToken);
                this.requestUpdatePlayerReconnToken(reconnP,reconnToken);
                client.send("S2C", JSON.stringify({ cmd: "S2C_allOpenedGrids", grids: this.getAllOpenedGrids() }));
            }
          } else {
            console.log("failed:", client.sessionId);

          }
        });
      }

in the code above,i want to save the newer reconnectionToken to my database ,and when i login in the same account in anther web,i want to get back the reconnectionToken to reconnect back.but ,i found client._reconnectionToken is not the newer reconnectionToken,so it will be expired when i use it. how can i get the newer token in this situation.thanks all !

[endel]

Hi @VicentGogh2025, when the allowReconnection() resolves, you'll receive the new client instance. The new client instance has the new reconnection token.

this.allowReconnection(client, 6000).then((newClient) => {
  // the reconnection has been reestablished here
  console.log("new reconnection token: ", newClient._reconnectionToken);
}).catch(() => {
  console.log("reconnection failed:", client.sessionId);
});

On the new version 0.16, the ._reconnectionToken property has been renamed simply to .reconnectionToken - also, for convenience, the previous client instance will have its .reconnectionToken property updated after the reconnection is successful for easy access. (See sources)

[VicentGogh2025]

yes，thank you!,

[VicentGogh2025]

https://github.com/orgs/colyseus/discussions/595
thanks this friend，i found the way。but，the best way is get newClient directly as endel show me.