-
Notifications
You must be signed in to change notification settings - Fork 171
/
BalancedBinaryTree.java
36 lines (35 loc) · 1.05 KB
/
BalancedBinaryTree.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
/*
Author: King, [email protected]
Date: Oct 07, 2014
Problem: Balanced Binary Tree
Difficulty: Easy
Source: https://oj.leetcode.com/problems/balanced-binary-tree/
Notes:
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which
the depth of the two subtrees of every node never differ by more than 1.
Solution: DFS.
*/
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isBalanced(TreeNode root) {
if (root == null) return true;
return isBalancedRe(root) > -1;
}
public int isBalancedRe(TreeNode root) {
if (root == null) return 0;
int left = isBalancedRe(root.left);
int right = isBalancedRe(root.right);
if (left == -1 || right == -1) return -1;
if (Math.abs(left - right) > 1) return -1;
return Math.max(left, right) + 1;
}
}