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Results of GPT-4 on HumanEval/159

Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%

Prompt

Tokens: 303

def eat(number, need, remaining):
    """
    You're a hungry rabbit, and you already have eaten a certain number of carrots,
    but now you need to eat more carrots to complete the day's meals.
    you should return an array of [ total number of eaten carrots after your meals,
                                    the number of carrots left after your meals ]
    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
    
    Example:
    * eat(5, 6, 10) -> [11, 4]
    * eat(4, 8, 9) -> [12, 1]
    * eat(1, 10, 10) -> [11, 0]
    * eat(2, 11, 5) -> [7, 0]
    
    Variables:
    @number : integer
        the number of carrots that you have eaten.
    @need : integer
        the number of carrots that you need to eat.
    @remaining : integer
        the number of remaining carrots thet exist in stock
    
    Constrain:
    * 0 <= number <= 1000
    * 0 <= need <= 1000
    * 0 <= remaining <= 1000

    Have fun :)
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def eat(number, need, remaining):
    """
    You're a hungry rabbit, and you already have eaten a certain number of carrots,
    but now you need to eat more carrots to complete the day's meals.
    you should return an array of [ total number of eaten carrots after your meals,
                                    the number of carrots left after your meals ]
    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
    
    Example:
    * eat(5, 6, 10) -> [11, 4]
    * eat(4, 8, 9) -> [12, 1]
    * eat(1, 10, 10) -> [11, 0]
    * eat(2, 11, 5) -> [7, 0]
    
    Variables:
    @number : integer
        the number of carrots that you have eaten.
    @need : integer
        the number of carrots that you need to eat.
    @remaining : integer
        the number of remaining carrots thet exist in stock
    
    Constrain:
    * 0 <= number <= 1000
    * 0 <= need <= 1000
    * 0 <= remaining <= 1000

    Have fun :)
    """if(need <= remaining):
        return [ number + need , remaining-need ]
    else:
        return [ number + remaining , 0]

Unit tests

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(5, 6, 10) == [11, 4], "Error"
    assert candidate(4, 8, 9) == [12, 1], "Error"
    assert candidate(1, 10, 10) == [11, 0], "Error"
    assert candidate(2, 11, 5) == [7, 0], "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(4, 5, 7) == [9, 2], "Error"
    assert candidate(4, 5, 1) == [5, 0], "Error"

Runs

✅ Run 1

Start time: 2023-07-18 17:44:38
Duration: 4.06s
Completion tokens: 42
Result: Pass

def eat(number, need, remaining):
    if need <= remaining:
        return [number + need, remaining - need]
    else:
        return [number + remaining, 0]

✅ Run 2

Start time: 2023-07-18 17:44:34
Duration: 3.43s
Completion tokens: 42
Result: Pass

def eat(number, need, remaining):
    if remaining >= need:
        return [number + need, remaining - need]
    else:
        return [number + remaining, 0]

✅ Run 3

Start time: 2023-07-18 17:44:31
Duration: 2.98s
Completion tokens: 42
Result: Pass

def eat(number, need, remaining):
    if remaining >= need:
        return [number + need, remaining - need]
    else:
        return [number + remaining, 0]

✅ Run 4

Start time: 2023-07-18 17:44:27
Duration: 3.65s
Completion tokens: 42
Result: Pass

def eat(number, need, remaining):
    if need <= remaining:
        return [number + need, remaining - need]
    else:
        return [number + remaining, 0]

✅ Run 5

Start time: 2023-07-18 17:44:06
Duration: 20.99s
Completion tokens: 305
Result: Pass

def eat(number, need, remaining):
    """
    You're a hungry rabbit, and you already have eaten a certain number of carrots,
    but now you need to eat more carrots to complete the day's meals.
    you should return an array of [ total number of eaten carrots after your meals,
                                    the number of carrots left after your meals ]
    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
    
    Example:
    * eat(5, 6, 10) -> [11, 4]
    * eat(4, 8, 9) -> [12, 1]
    * eat(1, 10, 10) -> [11, 0]
    * eat(2, 11, 5) -> [7, 0]
    
    Variables:
    @number : integer
        the number of carrots that you have eaten.
    @need : integer
        the number of carrots that you need to eat.
    @remaining : integer
        the number of remaining carrots thet exist in stock
    
    Constrain:
    * 0 <= number <= 1000
    * 0 <= need <= 1000
    * 0 <= remaining <= 1000

    Have fun :)
    """
    if need <= remaining:
        return [number + need, remaining - need]
    else:
        return [number + remaining, 0]

✅ Run 6

Start time: 2023-07-18 17:44:01
Duration: 5.01s
Completion tokens: 42
Result: Pass

def eat(number, need, remaining):
    if remaining >= need:
        return [number + need, remaining - need]
    else:
        return [number + remaining, 0]

✅ Run 7

Start time: 2023-07-18 17:43:56
Duration: 5.46s
Completion tokens: 49
Result: Pass

def eat(number, need, remaining):
    if remaining >= need:
        number += need
        remaining -= need
    else:
        number += remaining
        remaining = 0
    return [number, remaining]

✅ Run 8

Start time: 2023-07-18 17:43:51
Duration: 4.24s
Completion tokens: 49
Result: Pass

def eat(number, need, remaining):
    if remaining >= need:
        number += need
        remaining -= need
    else:
        number += remaining
        remaining = 0
    return [number, remaining]

✅ Run 9

Start time: 2023-07-18 17:43:46
Duration: 4.98s
Completion tokens: 42
Result: Pass

def eat(number, need, remaining):
    if remaining >= need:
        return [number + need, remaining - need]
    else:
        return [number + remaining, 0]

✅ Run 10

Start time: 2023-07-18 17:43:42
Duration: 4.57s
Completion tokens: 42
Result: Pass

def eat(number, need, remaining):
    if remaining >= need:
        return [number + need, remaining - need]
    else:
        return [number + remaining, 0]