Date: 18 July, 2023
Model: gpt-3.5-turbo
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%
Tokens: 213
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.
For example:
assert list_sort(["aa", "a", "aaa"]) => ["aa"]
assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
"""
The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.
For example:
assert list_sort(["aa", "a", "aaa"]) => ["aa"]
assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
"""lst.sort()
new_lst = []
for i in lst:
if len(i)%2 == 0:
new_lst.append(i)
return sorted(new_lst, key=len)
def check(candidate):
# Check some simple cases
assert candidate(["aa", "a", "aaa"]) == ["aa"]
assert candidate(["school", "AI", "asdf", "b"]) == ["AI", "asdf", "school"]
assert candidate(["d", "b", "c", "a"]) == []
assert candidate(["d", "dcba", "abcd", "a"]) == ["abcd", "dcba"]
# Check some edge cases that are easy to work out by hand.
assert candidate(["AI", "ai", "au"]) == ["AI", "ai", "au"]
assert candidate(["a", "b", "b", "c", "c", "a"]) == []
assert candidate(['aaaa', 'bbbb', 'dd', 'cc']) == ["cc", "dd", "aaaa", "bbbb"]
Start time: 2023-07-18 17:02:58
Duration: 2.27s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:55
Duration: 2.66s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:53
Duration: 2.27s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:51
Duration: 2.0s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:49
Duration: 1.92s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:47
Duration: 2.04s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:45
Duration: 1.98s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:43
Duration: 2.11s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:41
Duration: 2.02s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst
Start time: 2023-07-18 17:02:38
Duration: 2.26s
Completion tokens: 42
Result: Pass
def sorted_list_sum(lst):
lst = [word for word in lst if len(word) % 2 == 0]
lst.sort(key=lambda x: (len(x), x))
return lst