80.md

Results of Code LLama 34B on HumanEval/80

Date: 01 September, 2023
Model: codellama-34b-instruct
Temperature: 0.2
Passing runs: 10
Total runs: 10
Success rate: 100%

Prompt

def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def is_happy(s):
    """You are given a string s.
    Your task is to check if the string is happy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_happy(abcd) => True
    is_happy(aabb) => False
    is_happy(adb) => True
    is_happy(xyy) => False
    """if len(s) < 3:
      return False

    for i in range(len(s) - 2):
      
      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:
        return False
    return True

Unit tests

def check(candidate):

    # Check some simple cases
    assert candidate("a") == False , "a"
    assert candidate("aa") == False , "aa"
    assert candidate("abcd") == True , "abcd"
    assert candidate("aabb") == False , "aabb"
    assert candidate("adb") == True , "adb"
    assert candidate("xyy") == False , "xyy"
    assert candidate("iopaxpoi") == True , "iopaxpoi"
    assert candidate("iopaxioi") == False , "iopaxioi"

Runs

✅ Run 1

Start time: 2023-09-01 02:47:21
Duration: 5.69s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 2

Start time: 2023-09-01 02:50:21
Duration: 5.36s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 3

Start time: 2023-09-01 02:53:20
Duration: 13.63s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 4

Start time: 2023-09-01 02:56:15
Duration: 14.5s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 5

Start time: 2023-09-01 02:59:08
Duration: 5.11s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 6

Start time: 2023-09-01 03:02:15
Duration: 6.31s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 7

Start time: 2023-09-01 03:05:15
Duration: 12.88s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 8

Start time: 2023-09-01 03:08:19
Duration: 5.85s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 9

Start time: 2023-09-01 03:11:15
Duration: 5.55s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True

✅ Run 10

Start time: 2023-09-01 03:14:15
Duration: 5.15s
Result: Pass

def is_happy(s):
    if len(s) < 3:
        return False
    for i in range(len(s) - 2):
        if s[i] == s[i + 1] or s[i] == s[i + 2] or s[i + 1] == s[i + 2]:
            return False
    return True