32.md

Results of Code LLama 34B on HumanEval/32

Date: 01 September, 2023
Model: codellama-34b-instruct
Temperature: 0.2
Passing runs: 0
Total runs: 10
Success rate: 0%

Prompt

import math


def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])


def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only only zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

import math


def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])


def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only only zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """begin, end = -1., 1.
    while poly(xs, begin) * poly(xs, end) > 0:
        begin *= 2.0
        end *= 2.0
    while end - begin > 1e-10:
        center = (begin + end) / 2.0
        if poly(xs, center) * poly(xs, begin) > 0:
            begin = center
        else:
            end = center
    return begin

Unit tests

METADATA = {}


def check(candidate):
    import math
    import random
    rng = random.Random(42)
    import copy
    for _ in range(100):
        ncoeff = 2 * rng.randint(1, 4)
        coeffs = []
        for _ in range(ncoeff):
            coeff = rng.randint(-10, 10)
            if coeff == 0:
                coeff = 1
            coeffs.append(coeff)
        solution = candidate(copy.deepcopy(coeffs))
        assert math.fabs(poly(coeffs, solution)) < 1e-4

Runs

❌ Run 1

Start time: 2023-09-01 02:48:09
Duration: 20.17s
Result: Fail

import math

def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only one zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    n = len(xs)
    if n % 2 == 0 and xs[n-1] != 0:
        return None
    for i in range(n-1):
        if xs[i] == 0:
            return 0
    x = 1
    while x <= n:
        y = poly(xs, x)
        if y == 0:
            return x
        x += 1
    return None

❌ Run 2

Start time: 2023-09-01 02:51:09
Duration: 16.12s
Result: Fail

import math

def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only one zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    n = len(xs)
    if n % 2 == 0:
        return None
    if xs[n-1] == 0:
        return None
    x = -xs[0] / xs[n-1]
    for i in range(n-2, -1, -1):
        x = x - xs[i] / xs[n-1]
    return x

❌ Run 3

Start time: 2023-09-01 02:54:04
Duration: 18.37s
Result: Fail

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only one zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    # Find the largest non-zero coefficient
    largest_coeff = max(xs, key=abs)
    # Find the index of the largest non-zero coefficient
    largest_coeff_index = xs.index(largest_coeff)
    # Find the number of coefficients
    num_coeffs = len(xs)
    # Check if the number of coefficients is even
    if num_coeffs % 2 == 0:
        # If the number of coefficients is even, find the zero point
        zero_point = -largest_coeff / (xs[largest_coeff_index - 1] + xs[largest_coeff_index + 1])
    else:
        # If the number of coefficients is odd, find the zero point
        zero_point = -largest_coeff / (xs[largest_coeff_index - 1] + xs[largest_coeff_index + 1])
    return zero_point

❌ Run 4

Start time: 2023-09-01 02:57:02
Duration: 16.31s
Result: Fail

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only one zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    # Check if the list has an even number of coefficients
    if len(xs) % 2 == 1:
        raise ValueError("The list must have an even number of coefficients.")

    # Find the largest non-zero coefficient
    largest_coeff = max(xs, key=abs)

    # Check if the largest non-zero coefficient is positive
    if largest_coeff > 0:
        raise ValueError("The largest non-zero coefficient must be negative.")

    # Find the zero point
    zero_point = -largest_coeff / (xs[0] - largest_coeff)

    return zero_point

❌ Run 5

Start time: 2023-09-01 03:00:01
Duration: 17.29s
Result: Fail

import math

def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only only zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    if len(xs) % 2 == 0 and xs[-1] != 0:
        return None
    x = 0
    for i in range(len(xs) // 2):
        x += xs[i] * math.pow(x, i)
    return x

❌ Run 6

Start time: 2023-09-01 03:03:01
Duration: 19.86s
Result: Fail

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only one zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    # Find the largest non-zero coefficient
    largest_coeff = max(xs, key=abs)
    # Find the index of the largest non-zero coefficient
    largest_coeff_index = xs.index(largest_coeff)
    # Find the number of coefficients
    num_coeffs = len(xs)
    # Check if the number of coefficients is even
    if num_coeffs % 2 == 0:
        # If the number of coefficients is even, find the zero point
        zero_point = -largest_coeff / (num_coeffs - largest_coeff_index)
    else:
        # If the number of coefficients is odd, find the zero point
        zero_point = -largest_coeff / (num_coeffs - largest_coeff_index - 1)
    # Return the zero point
    return zero_point

❌ Run 7

Start time: 2023-09-01 03:06:05
Duration: 16.38s
Result: Fail

import math

def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only only zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    if len(xs) % 2 == 1:
        raise ValueError("xs must have an even number of coefficients")
    if xs[-1] == 0:
        raise ValueError("largest non-zero coefficient must be non-zero")
    x = 0
    while poly(xs, x) != 0:
        x += 1
    return x

❌ Run 8

Start time: 2023-09-01 03:09:10
Duration: 17.29s
Result: Fail

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only one zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    if len(xs) % 2 == 1:
        raise ValueError("xs must have an even number of coefficients")
    if xs[-1] == 0:
        raise ValueError("largest non-zero coefficient must be non-zero")
    x = 0
    for i in range(len(xs) // 2):
        x += xs[i] * math.pow(x, i)
    return x

❌ Run 9

Start time: 2023-09-01 03:12:04
Duration: 17.71s
Result: Fail

import math

def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only one zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    # Check if the input list has an even number of coefficients
    if len(xs) % 2 == 1:
        raise ValueError("The number of coefficients must be even.")

    # Check if the largest coefficient is non-zero
    if xs[-1] == 0:
        raise ValueError("The largest coefficient must be non-zero.")

    # Find the zero point by setting the polynomial equal to zero and solving for x
    x = -xs[-1] / xs[-2]

    # Return the zero point
    return x

❌ Run 10

Start time: 2023-09-01 03:15:07
Duration: 18.62s
Result: Fail

import math

def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    find_zero find x such that poly(x) = 0.
    find_zero returns only only zero point, even if there are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largest non zero coefficient as it guarantees
    a solution.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """
    if len(xs) % 2 == 1:
        raise ValueError("xs must have an even number of coefficients")
    if xs[-1] == 0:
        raise ValueError("largest non-zero coefficient must be non-zero")
    x = 0
    while poly(xs, x) != 0:
        x += 1
    return x