-
Notifications
You must be signed in to change notification settings - Fork 820
/
DungeonGame.java
81 lines (76 loc) · 2.97 KB
/
DungeonGame.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
/* (C) 2024 YourCompanyName */
package dynamic_programming;
import java.util.Arrays;
/**
* Created by gouthamvidyapradhan on 12/07/2017. The demons had captured the princess (P) and
* imprisoned her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid
* out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must
* fight his way through the dungeon to rescue the princess.
*
* <p>The knight has an initial health point represented by a positive integer. If at any point his
* health point drops to 0 or below, he dies immediately.
*
* <p>Some of the rooms are guarded by demons, so the knight loses health (negative integers) upon
* entering these rooms; other rooms are either empty (0's) or contain magic orbs that increase the
* knight's health (positive integers).
*
* <p>In order to reach the princess as quickly as possible, the knight decides to move only
* rightward or downward in each step.
*
* <p>
*
* <p>Write a function to determine the knight's minimum initial health so that he is able to rescue
* the princess.
*
* <p>For example, given the dungeon below, the initial health of the knight must be at least 7 if
* he follows the optimal path RIGHT-> RIGHT -> DOWN -> DOWN.
*
* <p>-2 (K) -3 3 -5 -10 1 10 30 -5 (P)
*
* <p>Notes:
*
* <p>The knight's health has no upper bound. Any room can contain threats or power-ups, even the
* first room the knight enters and the bottom-right room where the princess is imprisoned.
*
* <p>Solution: O(MxN log Integer.MAX_VALUE) Binary search the suitable initial health value in the
* range (1, Integer.MAX_VALUE) and do a top down DP to check the balance health when he reaches
* princess.
*/
public class DungeonGame {
private final int[] R = {0, -1};
private final int[] C = {-1, 0};
private int DP[][];
public static void main(String[] args) throws Exception {
int[][] dungeon = {{200}};
System.out.println(new DungeonGame().calculateMinimumHP(dungeon));
}
public int calculateMinimumHP(int[][] dungeon) {
DP = new int[dungeon.length][dungeon[0].length];
int l = 0, h = Integer.MAX_VALUE, ans = 0;
while (l <= h) {
int m = l + (h - l) / 2;
for (int i = 0; i < dungeon.length; i++) Arrays.fill(DP[i], Integer.MIN_VALUE);
DP[0][0] = m + dungeon[0][0];
if (dp(dungeon, dungeon.length - 1, dungeon[0].length - 1) > 0) {
ans = m;
h = m - 1;
} else {
l = m + 1;
}
}
return ans == 0 ? 1 : ans;
}
private int dp(int[][] dungeon, int r, int c) {
if (DP[r][c] != Integer.MIN_VALUE) return DP[r][c];
for (int i = 0; i < 2; i++) {
int newR = r + R[i];
int newC = c + C[i];
if (newR >= 0 && newR < dungeon.length && newC >= 0 && newC < dungeon[0].length) {
int life = dp(dungeon, newR, newC);
if (life <= 0) DP[r][c] = Math.max(DP[r][c], 0);
else DP[r][c] = Math.max(DP[r][c], dungeon[r][c] + life);
}
}
return DP[r][c];
}
}