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NextGreaterElementI.java
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NextGreaterElementI.java
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/* (C) 2024 YourCompanyName */
package array;
/**
* Created by gouthamvidyapradhan on 09/02/2018. You are given two arrays (without duplicates) nums1
* and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for
* nums1's elements in the corresponding places of nums2.
*
* <p>The Next Greater Number of a number x in nums1 is the first greater number to its right in
* nums2. If it does not exist, output -1 for this number.
*
* <p>Example 1: Input: nums1 = [4,1,2], nums2 = [1,3,4,2]. Output: [-1,3,-1] Explanation: For
* number 4 in the first array, you cannot find the next greater number for it in the second array,
* so output -1. For number 1 in the first array, the next greater number for it in the second array
* is 3. For number 2 in the first array, there is no next greater number for it in the second
* array, so output -1. Example 2: Input: nums1 = [2,4], nums2 = [1,2,3,4]. Output: [3,-1]
* Explanation: For number 2 in the first array, the next greater number for it in the second array
* is 3. For number 4 in the first array, there is no next greater number for it in the second
* array, so output -1. Note: All elements in nums1 and nums2 are unique. The length of both nums1
* and nums2 would not exceed 1000.
*/
public class NextGreaterElementI {
/**
* Main method
*
* @param args
* @throws Exception
*/
public static void main(String[] args) throws Exception {
int[] A = {4, 1, 2};
int[] B = {1, 3, 4, 2};
int[] result = new NextGreaterElementI().nextGreaterElement(A, B);
System.out.println(result);
}
public int[] nextGreaterElement(int[] nums1, int[] nums2) {
int[] result = new int[nums1.length];
for (int i = 0; i < nums1.length; i++) {
int n = nums1[i];
boolean found = false;
int nF = 0;
for (int j = 0; j < nums2.length; j++) {
if (nums2[j] == n) {
found = true;
}
if (found) {
if (nums2[j] > n) {
nF = nums2[j];
break;
}
}
}
if (found) {
result[i] = nF;
} else {
result[i] = -1;
}
}
return result;
}
}