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Non-lvalue can be assigned after simplifying the shift operation #32

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huangguiyang opened this issue Dec 8, 2016 · 0 comments
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@huangguiyang
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huangguiyang commented Dec 8, 2016

(i >> 0) = j;

After the simplify at simp.c, the expression 'i >> 0' will be simplified to 'i' which is an INDIR tree, thus the assignment check will be OK.

The same problem can be found in other identity simplification.

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