How to match "TOKEN anything up to the next newline"

[mark-summerfield]

I am learning Antlr 4.
To start with I'm trying to devise a simple .ini parser.
Example .ini file:

; test
; one comment
one = a string value
; two comment
two: 98.765

[group1]
; group1 comment
; three comment
three = true

[Group.Two]
; Group.Two comment
; key-four comment
key-four = 2025/4/16

Here's the grammar I've come up with:

grammar Ini;
options {caseInsensitive = true;}
ini : comment* anongroup? group* EOF ;
anongroup : groupbody ;
group : '[' ID ']' groupbody ;
groupbody : (entry | comment)+ ;
entry : key (':' | '=') value ;
comment : ';' line ;
key : ID ;
value : line ;
line : ~ ('\r' | '\n')+ ;
ID : ('A'..'Z' | '0'..'9') ('A'..'Z' | '0'..'9' | '_' | '-' | '.')* ;
WS : [ \t\r\n]+ ;

And here's the output when I dump the results:

line 1:1 reportAttemptingFullContext d=0 (ini), input='; '
line 1:0 no viable alternative at input ';'
line 15:15 token recognition error at: '/'
line 15:17 token recognition error at: '/'
; test
; one comment
one = a string value
; two comment
two: 98.765

[group1]
; group1 comment
; three comment
three = true

[Group.Two]
; Group.Two comment
; key-four comment
key-four = 2025416

The second line of the error message says "no viable alternative at input ';'", i.e., at the very first character in the example. However, as far as I can tell antlr should try comment which it should match at the ;. Nor do I understand why it has eaten the /s in the last line. So I can't see what I'm doing wrong.

[mark-summerfield]

I finally worked it out. Here's the modified grammar:

grammar Ini;
options {caseInsensitive = true;}

ini : comment* anongroup? group* EOF ;
anongroup : groupbody ;
group : '[' ID ']' groupbody ;
groupbody : (entry | comment)+ ;
entry : key (':' | '=') value? ;
key : ID ;
value : line ;
comment : ';' line ;
line : .+? ;
ID : ('A'..'Z' | '0'..'9') ('A'..'Z' | '0'..'9' | '_' | '-' | '.')* ;
WS : [ \t\r\n]+ -> skip;