如何用graph scope进行分页

[altqxdd]

想要按照按顶点的某个属性排序，如下：
g.V().order().by('address', asc).limit(10)

现在想取按address排序后第10～20个，或者20～30个，做一个分页的功能，有什么解决办法吗

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[siyuan0322]

Maybe you could use .next()
For example:

t = g.V().order().by('address', asc)
t.next(10)
t.next(10)

[altqxdd]

next 好像并不支持

[siyuan0322]

Please use bytecode mode, as follows:

g = interactive.traversal_source()
t = g.V().order().by('address', asc)
print(t.next(10))
print(t.next(10))

I'm not an expert of gremlin, perhaps @shirly121 could show how to use pagination in script mode.