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Consider ensuring the (k - 1)-th coefficient is non-zero #57

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psivesely opened this issue Mar 27, 2018 · 0 comments
Open

Consider ensuring the (k - 1)-th coefficient is non-zero #57

psivesely opened this issue Mar 27, 2018 · 0 comments

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@psivesely
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Currently there is a (1 / 256) ^ t probability that a secret byte can be recovered with k - t shares. This happens if the ak-1, ak-2, ..., ak-t coefficients are uniformly chosen to be 0. By ensuring the ak-1 coefficient is non-zero, this probability would be zero.

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