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my_Knapsack.c
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my_Knapsack.c
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#include <stdio.h>
#define NUM_OF_ITEMS 5
#define MAX_WEIGHT 20
typedef struct
{
char letter;
int weight;
int value;
} Item;
void addItems(Item[], int);
int getBestKnapsack(Item[], int, int, int[]);
int max(int, int);
int main() {
Item items[NUM_OF_ITEMS];
int result[NUM_OF_ITEMS] = {0}; // 1 - item was chosen, 0 - item wasn't chosen
addItems(items, NUM_OF_ITEMS);
printf("Maximum profit: %d\n", getBestKnapsack(items, NUM_OF_ITEMS, MAX_WEIGHT, result));
printf("Selected items:");
for (int i = 0; i < NUM_OF_ITEMS; i++){
if (result[i] == 1){
printf(" %c", items[i].letter);
}
}
return 0;
}
/* Add items to given items arrays, of size "size" */
void addItems(Item items[], int size){
for (int i = 0; i < size; i++){
scanf(" %c %d %d", &items[i].letter, &items[i].value, &items[i].weight);
}
}
/* Gets an array of items, it's size and the maximum weight allowed in the knapsack,
and a "result" array to return the selected items. Returns the max profit.
Using Dynamic Programming, see more: https://en.wikipedia.org/wiki/Knapsack_problem .
*/
int getBestKnapsack(Item items[], int numOfItems, int maxWeight, int result[]){
int dp[numOfItems+1][maxWeight+1]; // Used for Dynamic Programming
int i, j;
// i represents an item (num of available items), j represents the available weight in the bag
// row 'i' in "dp" represents cell 'i-1' in items/result
for (i = 0; i <= numOfItems; i++){
for (j = 0; j <= maxWeight; j++){
// No space for items || No items to put inside => 0 Profit
if (i == 0 || j == 0){
dp[i][j] = 0;
}
// There is space in the bag to include item i
else if(items[i-1].weight <= j){
// Check if it's better to include it or not
dp[i][j] = max(dp[i-1][j-items[i-1].weight] + items[i-1].value, dp[i-1][j]);
}
// Not enough space in the bag - don't include item
else{
dp[i][j] = dp[i-1][j];
}
}
}
i = numOfItems;
j = maxWeight;
// Trace chosen items (i and j start at the bottom left of the table)
while (i > 0 && j > 0){
if (dp[i-1][j] != dp[i][j]){
// Item was chosen, go to the point before choosing it
result[i-1] = 1;
j -= items[i-1].weight;
i--;
}
else{
// Item wasn't chosen, go to the item above and check there
result[i-1] = 0;
i--;
}
}
return dp[numOfItems][maxWeight];
}
int max(int a, int b){
return (a < b) ? b : a;
}