check: simplify code

No need to have the version in the key

Author: xavfernandez

pip/commands/check.py

@@ -20,14 +20,13 @@ def run(self, options, args):
         missing_reqs_dict, incompatible_reqs_dict = check_requirements(dists)
 
         for dist in dists:
-            key = '%s==%s' % (dist.project_name, dist.version)
-
-            for requirement in missing_reqs_dict.get(key, []):
+            for requirement in missing_reqs_dict.get(dist.key, []):
                 logger.info(
                     "%s %s requires %s, which is not installed.",
                     dist.project_name, dist.version, requirement.project_name)
 
-            for requirement, actual in incompatible_reqs_dict.get(key, []):
+            for requirement, actual in incompatible_reqs_dict.get(
+                    dist.key, []):
                 logger.info(
                     "%s %s has requirement %s, but you have %s %s.",
                     dist.project_name, dist.version, requirement,

pip/operations/check.py

@@ -5,16 +5,14 @@ def check_requirements(installed_dists):
     incompatible_reqs_dict = {}
 
     for dist in installed_dists:
-        key = '%s==%s' % (dist.project_name, dist.version)
-
         missing_reqs = list(get_missing_reqs(dist, installed_dists))
         if missing_reqs:
-            missing_reqs_dict[key] = missing_reqs
+            missing_reqs_dict[dist.key] = missing_reqs
 
         incompatible_reqs = list(get_incompatible_reqs(
             dist, installed_dists))
         if incompatible_reqs:
-            incompatible_reqs_dict[key] = incompatible_reqs
+            incompatible_reqs_dict[dist.key] = incompatible_reqs
 
     return (missing_reqs_dict, incompatible_reqs_dict)