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To support #200 we can create a new function tree_to_geopandas function that converts the "tree" key from the default result (python dictionary) into a geopandas dataframe.
Each Compass output row may have an entire tree, but, we do not want a GDF of trees (plural), we want instead to plot a single tree. Following the logic above, we can add one more index column so that each row is a link in a tree in a result:
for each Compass run result row _i_:
for each tree _j_:
for each tree branch _k_:
create row for `_index` _i_, `_tree` _k_, `_edge_id` edgeid(_k_)
The text was updated successfully, but these errors were encountered:
To support #200 we can create a new function
tree_to_geopandas
function that converts the"tree"
key from the default result (python dictionary) into a geopandas dataframe.Each Compass output row may have an entire tree, but, we do not want a GDF of trees (plural), we want instead to plot a single tree. Following the logic above, we can add one more index column so that each row is a link in a tree in a result:
The text was updated successfully, but these errors were encountered: