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[Enhancement] Access worksheet by name #75
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enhancement
New feature or request
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I came up with a little convenience function for this earlier today. Wasn't sure if you would rather have this functionality in CoreXLSX.swift or as an extension of Worksheet, so I figure I'd just post it here and let you decide where to put it. func getWorksheet(file: XLSXFile, name: String) throws -> Worksheet?
{
// Get the ID of the sheet we want
// NOTE:A workbook should not be able to have two worksheets with the same name...should we assume this is always true, though?
// If not, then we can use the commented code below.
let sheets = try file.parseWorkbooks()
.flatMap { $0.sheets.items }
.filter { $0.name == name }
if(sheets.isEmpty){ // no sheet with name
return nil
}
// Throw Error? - multiple sheets with same name (should not be possible)
// if(sheets.count > 1){}
let rID = sheets[0].relationship
//let rID = sheets.map { $0.relationship } // if multiple sheets with the same name is possible, use this to get an array of relationship IDs
// Explanation:
// parseDocumentPaths will give us something like: ["xl/workbook.xml"]
// get the relationships for that workbook (Path, [Relationship])
// CoreXLSX.Relationship(id: "rId3", type: CoreXLSX.Relationship.SchemaType.worksheet, target: "worksheets/sheet3.xml"),
// CoreXLSX.Relationship(id: "rId2", type: CoreXLSX.Relationship.SchemaType.worksheet, target: "worksheets/sheet2.xml"),
// CoreXLSX.Relationship(id: "rId1", type: CoreXLSX.Relationship.SchemaType.worksheet, target: "worksheets/sheet1.xml"),
// filter out the relationships with the IDs we want, and flatMap the paths
let paths = try file.parseDocumentPaths().map {
// For each document path, gets its relationships
try file.parseDocumentRelationships(path: $0) // returns (Path, [Relationship])
}.flatMap { (path, relationships) -> [String] in
let worksheets = relationships.items.filter { $0.id == rID }
//let worksheets = relationships.items.filter { rIDArr.contains($0.id) } // if multiple sheets with the same name is possible
guard !path.isRoot else { return worksheets.map { $0.target } }
// .rels file has paths relative to its directory,
// storing that path in `pathPrefix`
let pathPrefix = path.components.dropLast().joined(separator: "/")
return worksheets.map { "\(pathPrefix)/\($0.target)" }
}
if(paths.isEmpty){ // no paths for the worksheets
return nil
}
// Throw Error? - multiple paths for the worksheet name (should not be possible)
// if(paths > 1){}
return try file.parseWorksheet(at: paths[0])
} |
MaxDesiatov
changed the title
[Enhancement] Access worksheet by name.
[Enhancement] Access worksheet by name
Apr 6, 2020
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It would be convenient if there was something like
file.parseWorksheet(filepath: "xmlfile.xml", name: "myworksheet")
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